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QNEET-2016-Ch-1020: NEET 2016 Chemistry - Class 12 NEET-2016-Ch-1020 Solution: Which one of the following orders is correct for the bond…

Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules? Br2>I2>F2>Cl2Br_2 > I_2 > F_2 > Cl_2 F2>Cl2>Br2>I2F_2 > Cl_2 > Br_2 > I_2 I2>Br2>Cl2>F2I_2 > Br_2 > Cl_2 > F_2 Cl2>Br2>F2>I2Cl_2 > Br_2 > F_2 > I_2

Multiple Choice Options

  • A Br 2 > I 2 > F 2 > Cl 2
  • B F 2 > Cl 2 > Br 2 > I 2
  • C I 2 > Br 2 > Cl 2 > F 2
  • D Cl 2 > Br 2 > F 2 > I 2

Step-by-Step Verified Solution

Bond dissociation enthalpy decreases as the bond distance increases from F2 to I2. This is due to increase in the size of the atom, on moving from F to I. F � F bond dissociation enthalpy is smaller then Cl � Cl and even smaller than Br � Br. This is because F atom is very small and hence the three lone pairs of electrons on each F atom repel the bond pair holding the F-atoms in F 2 molecules. The order of bond dissociation enthalpy is : Cl 2 > Br 2 > F 2 > I 2

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