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QNEET-2016-Ch-1013: NEET 2016 Chemistry - Class 11 NEET-2016-Ch-1013 Solution: Consider the following liquid-vapour equilibrium. Liquid …

Consider the following liquid-vapour equilibrium. Liquid

\rightleftharpoons

Vapour Which of the following relations is correct?

\frac{d\ln P}{dT^2} = \frac{\Delta H_v}{T^2}

\frac{d\ln P}{dT} = \frac{\Delta H_v}{RT^2}

\frac{d\ln G}{dT^2} = \frac{\Delta H_v}{RT^2}

\frac{d\ln P}{dT} = \frac{\Delta H_v}{RT}

A ${{d\ln P} \over {d{T^2}}} = {{ - \Delta {H_v}} \over {{T^2}}}$ d T 2 d ln P _ = T 2 _ _ H v _ _
B ${{d\ln P} \over {dT}} = {{\Delta {H_v}} \over {R{T^2}}}$ d T d ln P _ = R T 2 _ H v _ _
C ${{d\ln G} \over {d{T^2}}} = {{\Delta {H_v}} \over {R{T^2}}}$ d T 2 d ln G _ = R T 2 _ H v _ _
D ${{d\ln P} \over {dT}} = {{ - \Delta {H_v}} \over {RT}}$ d T d ln P _ = RT _ _ H v _ _

Step-by-Step Verified Solution

This is Clausius-Clapeyron equation. d ln _ P d T = _ H v R T 2