Verified Solution • 2025–26 Session moderate

QNEET-2016-Ch-1010: NEET 2016 Chemistry - Class 12 NEET-2016-Ch-1010 Solution: The ionic radii of \(A^+\) and \(B^-\) ions are \(0.98…

The ionic radii of

A^+

and

B^-

ions are

0.98 \times 10^{-10}\ \text{m}

and

1.81 \times 10^{-10}\ \text{m}

. The coordination number of each ion in AB is 8 2 6 4

Multiple Choice Options

Step-by-Step Verified Solution

From radius ratio, r + r _ = 0.98 _ 10 _ 10 1.81 _ 10 _ 10 = 0.541 It lies in the range of 0.414 to 0.732 hence coordination number of each ion will be 6 as the compound will have NaCl type structure i.e., octahedral arrangement.

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