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QAIPM-2015-Ph-1351: NEET 2015 Physics - Class 11 AIPM-2015-Ph-1351 Solution: A particle is executing SHM along a straight line. Its…

A particle is executing SHM along a straight line. Its velocities at distances x1x_1 and x2x_2 from the mean position are V1V_1 and V2V_2 respectively. Its time period is 2πx12+x22V12+V222\pi\sqrt{\frac{x_1^2+x_2^2}{V_1^2+V_2^2}} 2πx12−x22V12−V222\pi\sqrt{\frac{x_1^2-x_2^2}{V_1^2-V_2^2}} 2πV12+V22x12+x222\pi\sqrt{\frac{V_1^2+V_2^2}{x_1^2+x_2^2}} 2πV12−V22x22−x122\pi\sqrt{\frac{V_1^2-V_2^2}{x_2^2-x_1^2}}

Multiple Choice Options

  • A 2πV12+V22x12+x222\pi \sqrt {{{V_1^2 + V_2^2} \over {x_1^2 + x_2^2}}} 2 � x 1 2 _ + x 2 2 _ V 1 2 _ + V 2 2 _ _ _
  • B 2πV12−V22x12−x222\pi \sqrt {{{V_1^2 - V_2^2} \over {x_1^2 - x_2^2}}} 2 � x 1 2 _ _ x 2 2 _ V 1 2 _ _ V 2 2 _ _ _
  • C 2πx12+x22V12+V222\pi \sqrt {{{x_1^2 + x_2^2} \over {V_1^2 + V_2^2}}} 2 � V 1 2 _ + V 2 2 _ x 1 2 _ + x 2 2 _ _ _
  • D 2πx22−x12V12−V222\pi \sqrt {{{x_2^2 - x_1^2} \over {V_1^2 - V_2^2}}} 2 � V 1 2 _ _ V 2 2 _ x 2 2 _ _ x 1 2 _ _ _

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