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QAIPM-2015-Ph-1343: NEET 2015 Physics - Class 12 AIPM-2015-Ph-1343 Solution: Consider 3rd orbit of \(He^+\) (Helium) using non-relativistic…

Consider 3rd orbit of He+He^+ (Helium) using non-relativistic approach the speed of electron in this orbit will be [given K = 9×1099 \times 10^9 constant Z = 2 and h (Planck's Constant) = 6.6×10−34 J s6.6 \times 10^{-34}\ \text{J s}] 0.73×106 m/s0.73 \times 10^6\ \text{m/s} 3.0×108 m/s3.0 \times 10^8\ \text{m/s} 2.92×106 m/s2.92 \times 10^6\ \text{m/s} 1.46×106 m/s1.46 \times 10^6\ \text{m/s}

Multiple Choice Options

  • A 0.73 ×\times _ 10 6 m/s
  • B 3.0 ×\times _ 10 8 m/s
  • C 2.92 ×\times _ 10 6 m/s
  • D 1.46 ×\times _ 10 6 m/s

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