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QAIPM-2015-Ph-1333: NEET 2015 Physics - Class 12 AIPM-2015-Ph-1333 Solution: A radiation of energy 'E' falls normally on a perfectly…

A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (C = Velocity of light) 2EC2\frac{2E}{C^2} EC2\frac{E}{C^2} EC\frac{E}{C} 2EC\frac{2E}{C}

Multiple Choice Options

  • A 2EC2{{2E} \over {{C^2}}} C 2 2 E _
  • B EC2{E \over {{C^2}}} C 2 E _
  • C EC{E \over C} C E _
  • D 2EC{{2E} \over C} C 2 E _

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