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QAIPM-2015-Ph-1332: NEET 2015 Physics - Class 12 AIPM-2015-Ph-1332 Solution: A conducting square frame of side 'a' and a long straight wire…

A conducting square frame of side 'a' and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity 'V'. The emf induced in the frame will be proportional to 1(2x+a)2\frac{1}{(2x+a)^2} 1(2x−a)(2x+a)\frac{1}{(2x-a)(2x+a)} 1x2\frac{1}{x^2} 1(2x−a)2\frac{1}{(2x-a)^2}

Multiple Choice Options

  • A 1(2x+a)2{1 \over {{{\left( {2x + a} \right)}^2}}} ( 2 x + a ) 2 1 _
  • B 1(2x−a)(2x+a){1 \over {\left( {2x - a} \right)\left( {2x + a} \right)}} ( 2 x _ a ) ( 2 x + a ) 1 _
  • C 1x2{1 \over {{x^2}}} x 2 1 _
  • D 1(2x−a)2{1 \over {{{\left( {2x - a} \right)}^2}}} ( 2 x _ a ) 2 1 _

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