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QAIPM-2015-Ph-1268: NEET 2015 Physics - Class 11 AIPM-2015-Ph-1268 Solution: A remote-sensing satellite of earth revolves in a circular…

A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25×106 m0.25 \times 10^6\ \text{m} above the surface of earth. If earth's radius is 6.38×106 m6.38 \times 10^6\ \text{m} and g = 9.8 ms−2\text{ms}^{-2} then the orbital speed of the satellite is 7.76 km s−17.76\ \text{km s}^{-1} 9.13 km s−19.13\ \text{km s}^{-1} 6.67 km s−16.67\ \text{km s}^{-1} 8.56 km s−18.56\ \text{km s}^{-1}

Multiple Choice Options

  • A 7.76 km s −- _ 1
  • B 9.13 km s −- _ 1
  • C 6.67 km s −- _ 1
  • D 8.56 km s −- _ 1

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