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QAIPM-2014-Ph-1442: NEET 2014 Physics - Class 12 AIPM-2014-Ph-1442 Solution: The binding energy per nucleon of \(_3^7Li\) and \(_2^4He\)…

The binding energy per nucleon of 37Li_3^7Li and 24He_2^4He nuclei are 5.60 MeV and 7.06 MeV respectively. In the nuclear reaction 37Li+11H→24He+24He+Q_3^7Li + _1^1H \rightarrow _2^4He + _2^4He + Q the value of energy Q released is 19.6 MeV -2.4 MeV 8.4 MeV 17.3 MeV

Multiple Choice Options

  • A 19.6 MeV
  • B −- _ 2.4 MeV
  • C 8.4 MeV
  • D 17.3 MeV

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