Verified Solution • 2025–26 Session moderate

QAIPM-2014-Ph-1440: NEET 2014 Physics - Class 11 AIPM-2014-Ph-1440 Solution: A certain number of spherical drops of a liquid of radius r…

A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V. If T is the surface tension of the liquid then energy = 4VT(1r−1R)4VT(\frac{1}{r}-\frac{1}{R}) is released. energy = 3VT(1r+1R)3VT(\frac{1}{r}+\frac{1}{R}) is absorbed. energy = 3VT(1r−1R)3VT(\frac{1}{r}-\frac{1}{R}) is released energy is neither released nor absorbed.

Multiple Choice Options

  • A energy = 4VT (1r−1R)\left( {{1 \over r} - {1 \over R}} \right) ( r 1 _ _ R 1 _ ) is released.
  • B energy = 3VT (1r+1R)\left( {{1 \over r} + {1 \over R}} \right) ( r 1 _ + R 1 _ ) is absorbed.
  • C energy = 3VT (1r−1R)\left( {{1 \over r} - {1 \over R}} \right) ( r 1 _ _ R 1 _ ) is released
  • D energy is neither released nor absorbed.

Step-by-Step Verified Solution

Comprehensive step-by-step solution and verified mathematical derivation available.

Related Learning Resources & Exam Preparation