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QAIPM-2014-Ph-1439: NEET 2014 Physics - Class 11 AIPM-2014-Ph-1439 Solution: A particle is moving such that its position coordinates (x y)…

A particle is moving such that its position coordinates (x y) are (2 m 3 m) at time t = 0 (6 m 7 m) at time t = 2 s and (13 m 14 m) at time t = 5 s. Average velocity vector (v⃗av\vec{v}_{av}) from t = 0 to t = 5 s is 15(13i^+14j^)\frac{1}{5}(13\hat{i}+14\hat{j}) 73(i^+j^)\frac{7}{3}(\hat{i}+\hat{j}) 2(i^+j^)2(\hat{i}+\hat{j}) 115(i^+j^)\frac{11}{5}(\hat{i}+\hat{j})

Multiple Choice Options

  • A 15(13i^+14j^){1 \over 5}\left( {13\widehat i + 14\widehat j} \right) 5 1 _ ( 13 i + 14 j _ )
  • B 73(i^+j^){7 \over 3}\left( {\widehat i + \widehat j} \right) 3 7 _ ( i + j _ )
  • C 2(i^+j^)2\left( {\widehat i + \widehat j} \right) 2 ( i + j _ )
  • D 115(i^+j^){11 \over 5}\left( {\widehat i + \widehat j} \right) 5 11 _ ( i + j _ )

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