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QAIPM-2014-Ph-1410: NEET 2014 Physics - Class 11 AIPM-2014-Ph-1410 Solution: Steam at \(100^ C\) is passed into 20 g of water at \(10^ C\).…

Steam at 100∘C100^\circ C is passed into 20 g of water at 10∘C10^\circ C. When water acquires a temperature of 80∘C80^\circ C the mass of water present will be [Take specific heat of water = 1 cal g−1 ∘C−1g^{-1}\ ^\circ C^{-1} and latent heat of steam = 540 cal g−1g^{-1}] 24 g 31.5 g 42.5 g 22.5 g

Multiple Choice Options

  • A 24 g
  • B 31.5 g
  • C 42.5 g
  • D 22.5 g

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