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QAIPM-2014-Ph-1407: NEET 2014 Physics - Class 12 AIPM-2014-Ph-1407 Solution: Two identical long conducting wires AOB and COD are placed at…

Two identical long conducting wires AOB and COD are placed at right angle to each other with one above other such that O is their common point for the two. The wires carry

I_1

and

I_2

currents respectively. Point P is lying at distance d from O along a direction perpendicular to the plane containing the wires. The magnetic field at the point P will be

\frac{\mu_0}{2\pi d}(I_2-I_1)

\frac{\mu_0}{2\pi d}(I_1+I_2)

\frac{\mu_0}{2\pi d}(I_1^2-I_2^2)

\frac{\mu_0}{2\pi d}(I_1^2+I_2^2)^{1/2}

Multiple Choice Options

A ${{{\mu _0}} \over {2\pi d}}\left( {{{{I_1}} \over {{I_2}}}} \right)$ 2 � d _ 0 _ _ ( I 2 _ I 1 _ _ )
B ${{{\mu _0}} \over {2\pi d}}\left( {{I_1} + {I_2}} \right)$ 2 � d _ 0 _ _ ( I 1 _ + I 2 _ )
C ${{{\mu _0}} \over {2\pi d}}\left( {I_1^2 - I_2^2} \right)$ 2 � d _ 0 _ _ ( I 1 2 _ _ I 2 2 _ )
D ${{{\mu _0}} \over {2\pi d}}{\left( {I_1^2 + I_2^2} \right)^{1/2}}$ 2 � d _ 0 _ _ ( I 1 2 _ + I 2 2 _ ) 1/2

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