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QAIPM-2014-Ph-1404: NEET 2014 Physics - Class 11 AIPM-2014-Ph-1404 Solution: If $n_1 n_2$ and $n_3$ are the fundamental frequencies of…

n_1 n_2

and

n_3

are the fundamental frequencies of three segments into which a string is divided then the original fundamental frequency n of the string is given by

\frac{1}{n} = \frac{1}{n_1} + \frac{1}{n_2} + \frac{1}{n_3}

\frac{1}{\sqrt{n}} = \frac{1}{\sqrt{n_1}} + \frac{1}{\sqrt{n_2}} + \frac{1}{\sqrt{n_3}}

\sqrt{n} = \sqrt{n_1} + \sqrt{n_2} + \sqrt{n_3}

n = n_1 + n_2 + n_3

A ${1 \over n} = {1 \over {{n_1}}} + {1 \over {{n_2}}} + {1 \over {{n_3}}}$ n 1 _ = n 1 _ 1 _ + n 2 _ 1 _ + n 3 _ 1 _
B ${1 \over {\sqrt n }} = {1 \over {\sqrt {{n_1}} }} + {1 \over {\sqrt {{n_2}} }} + {1 \over {\sqrt {{n_3}} }}$ n _ 1 _ = n 1 _ _ 1 _ + n 2 _ _ 1 _ + n 3 _ _ 1 _
C $\sqrt n = \sqrt {{n_1}} + \sqrt {{n_2}} + \sqrt {{n_3}}$ n _ = n 1 _ _ + n 2 _ _ + n 3 _ _
D n $=$ = n 1 + n 2 + n 3

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