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QNEET-2013-Ph-1618: NEET 2013 Physics - Class 11 NEET-2013-Ph-1618 Solution: The length of the wire between two ends of a sonometer is 100…

The length of the wire between two ends of a sonometer is 100 cm. What should be the positions of two bridges below the wire so that the three segments of the wire have their fundamental frequencies in the ratio 1:3:5. 150023 cm50023 cm\frac{1500}{23}\ \text{cm} \frac{500}{23}\ \text{cm} 150023 cm30023 cm\frac{1500}{23}\ \text{cm} \frac{300}{23}\ \text{cm} 30023 cm150023 cm\frac{300}{23}\ \text{cm} \frac{1500}{23}\ \text{cm} 150023 cm200023 cm\frac{1500}{23}\ \text{cm} \frac{2000}{23}\ \text{cm}

Multiple Choice Options

  • A 150023cm,50023cm{{1500} \over {23}}cm,{{500} \over {23}}cm 23 1500 _ c m , 23 500 _ c m
  • B 150023cm,{{1500} \over {23}}cm, 23 1500 _ c m , 30023cm{{300} \over {23}}cm 23 300 _ c m
  • C 30023cm,150023cm{{300} \over {23}}cm,{{1500} \over {23}}cm 23 300 _ c m , 23 1500 _ c m
  • D 150023cm,200023cm{{1500} \over {23}}cm,{{2000} \over {23}}cm 23 1500 _ c m , 23 2000 _ c m

Step-by-Step Verified Solution

From formula, f = 1 x T m _ 1 f _ l _ l 1 : l 2 : l 3 = 1 f 1 : 1 f 2 : 1 f 3 = f 2 f 3 : f 1 f 3 : f 1 f 2 [Given: f 1 : f 2 : f 3 = 1 : 3 : 5] = 15 : 5 : 3 Therefore the positions of two bridges below the wire are 15 _ 100 15 + 5 + 3 c m and 15 _ 100 + 5 _ 100 15 + 5 + 3 c m _ 1500 23 c m , 2000 23 c m

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