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QNEET-2013-Ph-1616: NEET 2013 Physics - Class 12 NEET-2013-Ph-1616 Solution: A source of light is placed at a distance of 50 cm from a photo …
A source of light is placed at a distance of 50 cm from a photo cell and the stopping potential is found to be . If the distance between the light source and photo cell is made 25 cm the new stopping potential will be:
Multiple Choice Options
- A V 0 /2
- B V 0
- C 4V 0
- D 2V 0
Step-by-Step Verified Solution
Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential = V 0 .