Verified Solution • 2025–26 Session moderate

QNEET-2013-Ph-1615: NEET 2013 Physics - Class 12 NEET-2013-Ph-1615 Solution: An electron in hydrogen atom makes a transition \(n_1 n_2\)…

An electron in hydrogen atom makes a transition n1→n2n_1 \rightarrow n_2 where n1n_1 and n2n_2 are principal quantum numbers of the two states. Assuming Bohr's model to be valid the time period of the electron in the initial state is eight times that in the final state. The possible values of n1n_1 and n2n_2 are n1=6n_1 = 6 and n2=2n_2 = 2 n1=8n_1 = 8 and n2=1n_2 = 1 n1=8n_1 = 8 and n2=2n_2 = 2 n1=4n_1 = 4 and n2=2n_2 = 2

Multiple Choice Options

  • A n 1 = 6 and n 2 = 2
  • B n 1 = 8 and n 2 = 1
  • C n 1 = 8 and n 2 = 2
  • D n 1 = 4 and n 2 = 2

Step-by-Step Verified Solution

As T _ n 3 _ T 1 T 2 = 8 T 2 T 2 = ( n 1 n 2 ) 3 Hence, n 1 = 2n 2

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