Verified Solution • 2025–26 Session moderate

QNEET-2013-Ph-1609: NEET 2013 Physics - Class 11 NEET-2013-Ph-1609 Solution: Two metal rods 1 and 2 of same lengths have same temperature…

Two metal rods 1 and 2 of same lengths have same temperature difference between their ends. Their thermal conductivities are K1K_1 and K2K_2 and cross sectional areas A1A_1 and A2A_2 respectively. If the rate of heat conduction in 1 is four times that in 2 then K1A1=4K2A2K_1A_1 = 4K_2A_2 K1A1=2K2A2K_1A_1 = 2K_2A_2 4K1A1=K2A24K_1A_1 = K_2A_2 K1A1=K2A2K_1A_1 = K_2A_2

Multiple Choice Options

  • A K 1 A 1 = 4K 2 A 2
  • B K 1 A 1 = 2K 2 A 2
  • C 4K 1 A 1 = K 2 A 2
  • D K 1 A 1 = K 2 A 2

Step-by-Step Verified Solution

Let L be length of each rod. Rate of heat flow in rod 1 for the temperature difference _ T is H 1 = K 1 A 1 _ T L Rate of heat flow in rod 2 for the same difference _ T is H 2 = K 2 A 2 _ T L As per question, H 1 = 4H 2 K 1 A 1 _ T L = 4 K 2 A 2 _ T L _ K 1 A 1 = 4 K 2 A 2

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