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QNEET-2013-Ph-1599: NEET 2013 Physics - Class 12 NEET-2013-Ph-1599 Solution: Two rods are joined end to end as shown. Both have a…

Two rods are joined end to end as shown. Both have a cross-sectional area of

0.01\ \text{cm}^2

. Each is 1 meter long. One rod is of copper with a resistivity of

1.7 \times 10^{-6}

ohm-centimeter the other is of iron with a resistivity of

10^{-5}

ohm-centimeter. How much voltage is required to produce a current of 1 ampere in the rods? 0.00145 V 0.0145 V

1.7 \times 10^{-6}\ \text{V}

0.117 V

Multiple Choice Options

A 0.00145 V
B 0.0145 V
C 1.7 $\times$ _ 10 $-$ _ 6 V
D 0.117 V

Step-by-Step Verified Solution

Copper rod and iron rod are joined in series. _ R = R C u + R F e = ( _ 1 + _ 2 ) _ A ( _ R = _ _ A ) From ohm�s law V = RI = (1.7 _ 10 �6 _ 10 �2 + 10 �5 _ 10 �2 ) � 0.01 _ 10 �4 volt = 0.117 volt ( _ I = 1A)

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