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QNEET-2013-Ph-1593: NEET 2013 Physics - Class 11 NEET-2013-Ph-1593 Solution: A system is taken from state a to state c by two paths adc and…

A system is taken from state a to state c by two paths adc and abc as shown in the figure. The internal energy at a is Ua=10 JU_a = 10\ \text{J}. Along the path adc the amount of heat absorbed dQ1=50 JdQ_1 = 50\ \text{J} and the work obtained dW1=20 JdW_1 = 20\ \text{J} whereas along the path abc the heat absorbed dQ2=36 JdQ_2 = 36\ \text{J}. The amount of work along the path abc is 10 J 12 J 36 J 6 J

Multiple Choice Options

  • A 10 J
  • B 12 J
  • C 36 J
  • D 6 J

Step-by-Step Verified Solution

From first law of thermodynamics Q a d c = _ U a d c + W a d c 50 J = _ U a d c + 20 J _ U a d c = 30 J Again Q a b c = _ U a b c + W a b c W a b c = Q a b c _ _ U a b c W a b c = 36 J _ 30 J W a b c = 6 J

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