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QNEET-2013-Ph-1586: NEET 2013 Physics - Class 12 NEET-2013-Ph-1586 Solution: The de-broglie wavelength of neutrons in thermal equilibrium at …

The de-broglie wavelength of neutrons in thermal equilibrium at temperature T is 3.08T A˚\frac{3.08}{\sqrt{T}}\ \text{\AA} 0.308T A˚\frac{0.308}{\sqrt{T}}\ \text{\AA} 0.0308T A˚\frac{0.0308}{\sqrt{T}}\ \text{\AA} 30.8T A˚\frac{30.8}{\sqrt{T}}\ \text{\AA}

Multiple Choice Options

  • A 3.08TA∘{{3.08} \over {\sqrt T }}\mathop A\limits^ \circ T _ 3.08 _ A _ _
  • B 0.308TA∘{{0.308} \over {\sqrt T }}\mathop A\limits^ \circ T _ 0.308 _ A _ _
  • C 0.0308TA∘{{0.0308} \over {\sqrt T }}\mathop A\limits^ \circ T _ 0.0308 _ A _ _
  • D 30.8TA∘{{30.8} \over {\sqrt T }}\mathop A\limits^ \circ T _ 30.8 _ A _ _

Step-by-Step Verified Solution

de Broglie wavelength of neutrons in thermal equilibrium at temperature T is _ = h 2 m k B T = 6.63 _ 10 _ 34 2 _ 1.67 _ 10 _ 27 _ 1.38 _ 10 _ 23 _ T = 30.8 T A _

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