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QNEET-2013-Ph-1585: NEET 2013 Physics - Class 12 NEET-2013-Ph-1585 Solution: An electromagnetic wave of frequency \( = 3.0\ {MHz}\) passes…

An electromagnetic wave of frequency ν=3.0 MHz\nu = 3.0\ \text{MHz} passes from vacuum into a dielectric medium with relative permittivity ϵr=4.0\epsilon_r = 4.0. Then Wavelength is doubled and frequency becomes half. Wavelength is halved and frequency remains unchanged. Wavelength and frequency both remain unchanged. Wavelength is doubled and frequency unchanged.

Multiple Choice Options

  • A Wavelength is doubled and frequency becomes half.
  • B Wavelength is halved and frequency remains unchanged.
  • C Wavelength and frequency both remain unchanged.
  • D Wavelength is doubled and frequency unchanged.

Step-by-Step Verified Solution

Velocity of electromagnetic wave in vacuum c = 1 _ 0 _ 0 = _ _ vacuum .....(1) Velocity of electromagnetic wave in the medium v medium = 1 _ 0 _ r _ 0 _ r = c _ r _ r For dielectric medium, _ r = 1 _ v medium = c _ r = c 4 = c 2 ........(2) Wavelength of the wave in medium _ medium = v m e d i u m _ = c 2 _ = _ v a c c u m 2

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