Verified Solution • 2025–26 Session moderate

QNEET-2013-Ph-1583: NEET 2013 Physics - Class 11 NEET-2013-Ph-1583 Solution: The radius of a planet is twice the radius of earth. Both have…

The radius of a planet is twice the radius of earth. Both have almost equal average mass densities. VPV_P and VEV_E are escape velocities of the planet and the earth respectively then VP=1.5VEV_P = 1.5V_E VP=2VEV_P = 2V_E VE=3VPV_E = 3V_P VE=1.5VPV_E = 1.5V_P

Multiple Choice Options

  • A V P = 1.5 V E
  • B V P = 2 V E
  • C V E = 3 V P
  • D V E = 1.5 V P

Step-by-Step Verified Solution

Here, R P = 2R E , _ E = _ P Escape velocity of the earth, V E = 2 G M E R E = 2 G R E ( 4 3 � R E 3 _ E ) = R E 8 3 � G _ E    ...(i) Escape velocity of the planet V P = 2 G M P R P = 2 G R P ( 4 3 � R P 3 _ P ) = R P 8 3 � G _ P    ...(ii) Divide (i) by (ii), we get V E V P = R E R P _ E _ P = R E 2 R E _ E _ E = 1 2 _ V P = 2 V E

Related Learning Resources & Exam Preparation