Verified Solution • 2025–26 Session moderate

QNEET-2013-Ph-1528: NEET 2013 Physics - Class 12 NEET-2013-Ph-1528 Solution: A wire of resistance \(4 \) is stretched to twice its original…

A wire of resistance 4Ω4\Omega is stretched to twice its original length. The resistance of stretched wire would be 8Ω8\Omega 16Ω16\Omega 2Ω2\Omega 4Ω4\Omega

Multiple Choice Options

  • A 8 Ω\Omega �
  • B 16 Ω\Omega �
  • C 2 Ω\Omega �
  • D 4 Ω\Omega �

Step-by-Step Verified Solution

Resistance of a wire, R = _ l A = 4 �    ...(i) When wire is stretched twice, its new length be l _ . Then l _ = 2 l On stretching volume of the wire remains constant. _ l A = l _ A _ where A' is the new cross-sectional area _ A _ = l l _ A = l 2 l A = A 2 _ Resistance of the stretched wire is R _ = _ l _ A _ = _ 2 l ( A / 2 ) = 4 _ l A = 4 ( 4 � ) = 16 �

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