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QNEET-2013-Ph-1527: NEET 2013 Physics - Class 11 NEET-2013-Ph-1527 Solution: A small object of uniform density rolls up a curved surface…
A small object of uniform density rolls up a curved surface with an initial velocity 'v'. It reaches upto a maximum height of with respect to the initial position. The object is hollow sphere disc ring solid sphere
Multiple Choice Options
- A hollow sphere
- B disc
- C ring
- D solid sphere
Step-by-Step Verified Solution
The kinetic energy of the rolling object is
converted into potential energy at height
h = ( 3 v 2 4 g )
So by the law of conservation of
mechanical energy, we have
1 2 M v 2 + 1 2 I _ 2 = M g h ( _ _ = v R )
1 2 M v 2 + 1 2 I ( v R ) 2 = M g ( 3 v 2 4 g )
1 2 I v 2 R 2 = 3 4 M v 2 _ 1 2 M v 2
1 2 I v 2 R 2 = 1 4 M v 2
_ I = 1 2 M R 2
Hence, the object is disc.