Verified Solution • 2025–26 Session moderate

QNEET-2013-Ph-1520: NEET 2013 Physics - Class 11 NEET-2013-Ph-1520 Solution: A wave travelling in the +ve x-direction having displacement…

A wave travelling in the +ve x-direction having displacement along y-direction as 1 m wavelength

2\pi

m and frequency of

\frac{1}{\pi}

Hz is represented by

y = \sin(10\pi x - 20\pi t)

y = \sin(2\pi x + 2\pi t)

y = \sin(x - 2t)

y = \sin(2\pi x - 2\pi t)

Multiple Choice Options

A y = sin(10 $\pi$ � x $-$ _ 20 $\pi$ � t)
B y = sin(2 $\pi$ � x + 2 $\pi$ � t)
C y = sin(x $-$ _ 2t)
D y $=$ = sin(2 $\pi$ � x $-$ _ 2 $\pi$ � t)

Step-by-Step Verified Solution

The standard equation of a wave travelling along +ve x-direction is given by y = A s i n ( k x _ _ t ) where A = Amplitude of the wave k = angular wave number _ = angular frequency of the wave Given: A = 1 m, _ = 2 � m , _ = 1 � H z As k = 2 � _ = 2 � 2 � = 1 _ = 2 � _ = 2 � _ 1 � = 2 _ The equation of the given wave is y = 1 sin (1x � 2t) = sin(x � 2t)

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