Verified Solution • 2025–26 Session moderate

QNEET-2013-Ph-1515: NEET 2013 Physics - Class 11 NEET-2013-Ph-1515 Solution: The upper half of an inclined plane of inclination \( \) is…

The upper half of an inclined plane of inclination θ\theta is perfectly smooth while lower half is rough. A block starting from rest at the top of the plane will again come to rest at the bottom if the coefficient of friction between the block and lower half of the plane is given by μ=2tan⁡θ\mu = \frac{2}{\tan\theta} μ=tan⁡θ\mu = \tan\theta μ=1tan⁡θ\mu = \frac{1}{\tan\theta} μ=2tan⁡θ\mu = \frac{2}{\tan\theta}

Multiple Choice Options

  • A μ\mu _ = 2 tan θ\theta _
  • B μ\mu _ = tan θ\theta _
  • C μ\mu _ = 1tan⁡θ{1 \over {\tan \theta }} tan _ 1 _
  • D μ=2tan⁡θ\mu = {2 \over {\tan \theta }} _ = tan _ 2 _

Step-by-Step Verified Solution

For upper half of inclined plane v 2 = u 2 + 2a S/2 = 2 (g sin _ ) S/2 = gS sin _ For lower half of inclined plane 0 = u 2 + 2 g (sin _ � _ cos _ ) S/2 _ _ g S sin _ _ = g S ( sin _ _ _ _ cos _ _ ) _ 2 sin _ _ = _ cos _ _ _ _ = 2 sin _ _ cos _ _ = 2 tan _ _

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