Verified Solution • 2025–26 Session moderate

QNEET-2013-Ph-1510: NEET 2013 Physics - Class 11 NEET-2013-Ph-1510 Solution: A stone falls freely under gravity. It covers distances \(h_1…

A stone falls freely under gravity. It covers distances h1h2h_1 h_2 and h3h_3 in the first 5 seconds the next 5 seconds and the next 5 seconds respectively. The relation between h1h2h_1 h_2 and h3h_3 is h2=3h1h_2 = 3h_1 and h3=3h2h_3 = 3h_2 h1=h2=h3h_1 = h_2 = h_3 h1=2h2=3h3h_1 = 2h_2 = 3h_3 h1=h23=h35h_1 = \frac{h_2}{3} = \frac{h_3}{5}

Multiple Choice Options

  • A h 2 = 3h 1 and h 3 = 3h 2
  • B h 1 = h 2 = h 3
  • C h 1 = 2h 2 = 3h 3
  • D h1{h_1} h 1 _ = h23{{{h_2}} \over 3} 3 h 2 _ _ = h35{{{h_3}} \over 5} 5 h 3 _ _

Step-by-Step Verified Solution

Here h = 1 2 g t 2 _ h 1 = 1 2 g ( 5 ) 2 = 125 h 1 + h 2 = 1 2 g ( 10 ) 2 = 500 _ h 2 = 375 h 1 + h 2 + h 3 = 1 2 g ( 15 ) 2 = 1125 _ h 3 = 625 _ h 2 = 3h 1 and h 3 = 5h 1 or h 1 = h 2 3 = h 3 5

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