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QNEET-2013-Ph-1503: NEET 2013 Physics - Class 12 NEET-2013-Ph-1503 Solution: For photoelectric emission from certain metal the cutoff…

For photoelectric emission from certain metal the cutoff frequency is ν\nu. If radiation of frequency 2ν2\nu impinges on the metal plate the maximum possible velocity of the emitted electron will be (m is the electron mass) 2hνm\sqrt{\frac{2h\nu}{m}} hν2m\sqrt{\frac{h\nu}{2m}} hνm\sqrt{\frac{h\nu}{m}} hνm\sqrt{\frac{h\nu}{m}}

Multiple Choice Options

  • A 2hυm\sqrt {{{2h\upsilon } \over m}} m 2 h _ _ _
  • B 2hυm2\sqrt {{{h\upsilon } \over m}} 2 m h _ _ _
  • C hυ(2m)\sqrt {{{h\upsilon } \over {\left( {2m} \right)}}} ( 2 m ) h _ _ _
  • D hυm\sqrt {{{h\upsilon } \over m}} m h _ _ _

Step-by-Step Verified Solution

Work function, _ = h _ According to Einstein�s photoelectric equation 1 2 m v max 2 = h(2 _ ) - h _ _ 1 2 m v max 2 = h _ _ v max 2 = 2 h _ m _ v max = 2 h _ m

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