Verified Solution • 2025–26 Session moderate

QNEET-2013-Ph-1502: NEET 2013 Physics - Class 12 NEET-2013-Ph-1502 Solution: The wavelength \( _e\) of an electron and \( _p\) of a photon…

The wavelength λe\lambda_e of an electron and λp\lambda_p of a photon of same energy E are related by λp∝λe\lambda_p \propto \lambda_e λp∝λe\lambda_p \propto \sqrt{\lambda_e} λp∝1λe\lambda_p \propto \frac{1}{\sqrt{\lambda_e}} λp∝λe2\lambda_p \propto \lambda_e^2

Multiple Choice Options

  • A λp∝λe{\lambda _p} \propto \sqrt {{\lambda _e}} _ p _ _ _ e _ _
  • B λp∝1λe{\lambda _p} \propto {1 \over {\sqrt {{\lambda _e}} }} _ p _ _ _ e _ _ 1 _
  • C λp∝λe2{\lambda _p} \propto {\lambda _e}^2 _ p _ _ _ e _ 2
  • D λp∝λe{\lambda _p} \propto {\lambda _e} _ p _ _ _ e _

Step-by-Step Verified Solution

Wavelength of an electron of energy E is _ e = h 2 m e E _ _ e 2 = h 2 2 m e E .....(1) Wavelength of a photon of same energy E is _ p = h c E _ E = h c _ p .....(2) Equating (1) and (2), we get h c _ p = h 2 2 m e _ e 2 _ _ p = 2 m e c h _ e 2 _ _ p _ _ e 2

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