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QNEET-2013-Ph-1488: NEET 2013 Physics - Class 11 NEET-2013-Ph-1488 Solution: A uniform force of \((3 {i} + {j})\) newton acts on a particle…
A uniform force of newton acts on a particle of mass 2 kg. Hence the particle is displaced from position metre to position metre. The work done by the force on the particle is 13 J 15 J 9 J 6 J
Multiple Choice Options
- A 13 J
- B 15 J
- C 9 J
- D 6 J
Step-by-Step Verified Solution
Here, F _ = ( 3 i ^ + j ^ ) N
Initial position, r 1 _ = ( 2 i ^ + k ^ ) m
Final position, r 2 _ = ( 4 i ^ + 3 j ^ _ k ^ ) m
Displacement, r _ = r 2 _ _ r 1 _
r _ = ( 4 i ^ + 3 j ^ _ k ^ ) m _ ( 2 i ^ + k ^ ) m = 2 i ^ + 3 j ^ _ 2 k ^ m
Work done, W = F _ . r _ = ( 3 i ^ + j ^ ) . ( 2 i ^ + 3 j ^ _ 2 k ^ ) = 6 + 3 = 9 J