Verified Solution • 2025–26 Session moderate

QNEET-2013-Ch-1572: NEET 2013 Chemistry - Class 12 NEET-2013-Ch-1572 Solution: Consider the half-cell reduction reaction \(Mn^{2+} + 2e^- Mn…

Consider the half-cell reduction reaction

Mn^{2+} + 2e^- \rightarrow Mn E^\circ = -1.18\ \text{V}

Mn^{2+} \rightarrow Mn^{3+} + e^- E^\circ = -1.51\ \text{V}

The

E^\circ

for the reaction

3Mn^{2+} \rightarrow Mn^0 + 2Mn^{3+}

and possibility of the forward reaction are respectively -4.18 V and yes +0.33 V and yes +2.69 V and no -2.69 V and no

Multiple Choice Options

A $-$ _ 4.18 V and yes
B + 0.33 V and yes
C + 2.69 V and no
D $-$ _ 2.69 V and no

Step-by-Step Verified Solution

Mn 2+ + 2e _ _ Mn, E o = _ 1.18 V Mn 2+ _ Mn 3+ + e _ , E o = _ 1.51 V 3Mn 2+ _ Mn o + 2Mn 3+ , _ E o = - 1.81 - 1.51 = _ 2.69 V Since _ E� is negative, _ _ G = �nFE�, _ G will have positive value so, forward reaction is not possible.

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