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QNEET-2013-Ch-1558: NEET 2013 Chemistry - Class 11 NEET-2013-Ch-1558 Solution: The values of \(K_{sp}\) of \(CaCO_3\) and \(CaC_2O_4\) are…

The values of KspK_{sp} of CaCO3CaCO_3 and CaC2O4CaC_2O_4 are 4.7×10−94.7 \times 10^{-9} and 1.3×10−91.3 \times 10^{-9} respectively at 25∘C25^\circ C. If the mixture of these two is washed with water what is the concentration of Ca2+Ca^{2+} ions in water? 5.831×10−5 M5.831 \times 10^{-5}\ \text{M} 6.856×10−5 M6.856 \times 10^{-5}\ \text{M} 3.606×10−5 M3.606 \times 10^{-5}\ \text{M} 7.746×10−5 M7.746 \times 10^{-5}\ \text{M}

Multiple Choice Options

  • A 5.831 ×\times _ 10 −- _ 5 M
  • B 6.856 ×\times _ 10 −- _ 5 M
  • C 3.606 ×\times _ 10 −- _ 5 M
  • D 7.746 ×\times _ 10 −- _ 5 M

Step-by-Step Verified Solution

CaCO 3 | _ | Ca 2+ | + | CO 3 2- x | x .tg {border-collapse:collapse;border-spacing:0;} .tg td{font-family:Arial, sans-serif;font-size:14px;padding:10px 5px;border-style:solid;border-width:0px;overflow:hidden;word-break:normal;border-top-width:1px;border-bottom-width:1px;border-color:black;} .tg th{font-family:Arial, sans-serif;font-size:14px;font-weight:normal;padding:10px 5px;border-style:solid;border-width:0px;overflow:hidden;word-break:normal;border-top-width:1px;border-bottom-width:1px;border-color:black;} .tg .tg-9wq8{border-color:inherit;text-align:center;vertical-align:middle} .tg .tg-c3ow{border-color:inherit;text-align:center;vertical-align:top} CaC 2 O 4 | _ | Ca 2+ | + | C 2 O 4 2- y | y [Ca 2+ ] = x + y Now, K sp (CaCO 3 ) = [Ca 2+ ] [CO 3 2- ] or 4.7 _ 10 �9 = (x + y)x .......(1) similarly, K sp (CaC 2 O 4 ) = [Ca 2+ ] [C 2 O 4 2� ] or 1.3 _ 10 �9 = (x + y)y .......(2) Dividing equation (1) and (2), we get x y = 3.6 _ x = 3.6y Putting in equation (2) we get y(3.6y + y) = 1.3 _ 10 �9 _ y = 1.68 _ 10 -5 and x = 3.6 _ 1.68 _ 10 -5 = 6.048 _ 10 -5 _ [Ca 2+ ] = (x + y) = (6.048 _ 10 -5 ) + (1.68 _ 10 -5 ) _ [Ca 2+ ] = 7.746 _ 10 �5 M

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