Verified Solution • 2025–26 Session moderate

QNEET-2013-Ch-1541: NEET 2013 Chemistry - Class 11 NEET-2013-Ch-1541 Solution: According to law of photochemical equivalence the energy…

According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as (h = 6.62×10−27 ergs6.62 \times 10^{-27}\ \text{ergs} c = 3×1010 cm s−13 \times 10^{10}\ \text{cm s}^{-1} NA=6.02×1023 mol−1N_A = 6.02 \times 10^{23}\ \text{mol}^{-1}) 1.196×1081.196 \times 10^8 2.859×1052.859 \times 10^5 2.859×10162.859 \times 10^{16} 1.196×10161.196 \times 10^{16}

Multiple Choice Options

  • A 1.196×108λ{{1.196 \times {{10}^8}} \over \lambda } _ 1.196 _ 10 8 _
  • B 2.859×105λ{{2.859 \times {{10}^5}} \over \lambda } _ 2.859 _ 10 5 _
  • C 2.859×1016λ{{2.859 \times {{10}^{16}}} \over \lambda } _ 2.859 _ 10 16 _
  • D 1.196×1016λ{{1.196 \times {{10}^{16}}} \over \lambda } _ 1.196 _ 10 16 _

Step-by-Step Verified Solution

E = h c N A _ = 6.62 _ 10 _ 27 _ 3 _ 10 10 _ 6.02 _ 10 23 _ = 1.1955 _ 10 8 _ = 1.196 _ 10 8 _ ergs mol -1

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