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QNEET-2013-Ch-1486: NEET 2013 Chemistry - Class 11 NEET-2013-Ch-1486 Solution: \(6.02 10^{20}\) molecules of urea present in 100 mL of its…

6.02×10206.02 \times 10^{20} molecules of urea present in 100 mL of its solution. The concentration of solution is 0.001 M 0.1 M 0.02 M 0.01 M

Multiple Choice Options

  • A 0.001 M
  • B 0.1 M
  • C 0.02 M
  • D 0.01 M

Step-by-Step Verified Solution

Moles of urea = 6.02 _ 10 20 6.02 _ 10 23 = 0.001 Concentration of solution = 0.001 100 _ 1000 = 0.01 M

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