Verified Solution • 2025–26 Session moderate

QNEET-2013-Ch-1485: NEET 2013 Chemistry - Class 12 NEET-2013-Ch-1485 Solution: What is the activation energy for a reaction if its rate…

What is the activation energy for a reaction if its rate doubles when the temperature is raised from

20^\circ C

35^\circ C

? (R = 8.314 J

mol^{-1} K^{-1}

) 34.7 kJ

mol^{-1}

15.1 kJ

mol^{-1}

342 kJ

mol^{-1}

269 kJ

mol^{-1}

Multiple Choice Options

A 34.7 kJ mol $-$ _ 1
B 15.1 kJ mol $-$ _ 1
C 342 kJ mol $-$ _ 1
D 269 kJ mol $-$ _ 1

Step-by-Step Verified Solution

log _ k 2 k 1 = E a 2.303 R ( 1 T 1 _ 1 T 2 ) Initial temperature, T 1 = 20 + 273 = 293 K Final temperature, T 2 = 35 + 273 = 308 K R = 8.314 JK �1 mol �1 As rate becomes double on raising temperature _ r 2 = 2r 1 As rate constant, k � r k 2 = 2k 1 _ log _ 2 = E a 2.303 _ 8.314 ( 1 293 _ 1 308 ) _ 0.301 = E a 19.147 _ 15 293 _ 308 _ E a = 34673 J mol �1 = 34.7 kJ mol �1

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