QNEET-2013-Ch-1476: NEET 2013 Chemistry - Class 11 NEET-2013-Ch-1476 Solution: \(KMnO_4\) can be prepared from \(K_2MnO_4\) as per the…

KOH is the base thus, it gives OH � ions thus it cannot remove OH � ions from reaction mixture but it adds on the concentration of OH � ions. So, an acid must be added but if a strong acid is added to the reaction mixture then in acidic condition the MnO 4 � formed reduces to give Mn 2+ thus, HCl which is a strong acid and SO 2 which on treating with water forms a strong H 2 SO 4 cannot be used for this purpose. Thus, CO 2 which forms H 2 CO 3 a weak acid reacts to remove OH � but not that much acidic that MnO 4 � undergo reduction. Thus, CO 2 is used for this reaction for completion.