Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ph-1766: NEET 2012 Physics - Class 11 AIPM-2012-Ph-1766 Solution: A thermodynamic system is taken through the cycle ABCD as shown …

A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is 2PV 4PV

\frac{1}{2}PV

Multiple Choice Options

A $\theta$ _ = tan $-$ _ 1 $\left( {{1 \over 4}} \right)$ ( 4 1 _ )
B $\theta$ _ = tan $-$ _ 1 (4)
C $\theta$ _ = tan $-$ _ 1 (2)
D $\theta$ _ = 45 o

Step-by-Step Verified Solution

Horizontal range R = u 2 sin _ 2 _ g ......(1) Maximum height H = u 2 sin 2 _ 2 g .....(2) According to the problem R = H u 2 sin _ 2 _ g = u 2 sin 2 _ 2 g _ 2 sin _ _ cos _ _ = sin 2 _ 2 2 cos _ _ = sin _ _ 2 _ cot _ _ = 1 4 _ tan _ _ = 4 _ _ = tan _ 1 ( 4 )

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