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QAIPM-2012-Ph-1749: NEET 2012 Physics - Class 11 AIPM-2012-Ph-1749 Solution: A solid cylinder of mass 3 kg is rolling on a horizontal…
A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity . It collides with a horizontal spring of force constant . The maximum compression produced in the spring will be
Multiple Choice Options
- A 0.5 m
- B 0.6 m
- C 0.7 m
- D 0.2 m
Step-by-Step Verified Solution
At maximum compression the solid cylinder
will stop so loss in K.E. of cylinder = gain in P.E.
of spring
_ 1 2 m v 2 + 1 2 I _ 2 = 1 2 k x 2
_ 1 2 m v 2 + 1 2 m R 2 2 ( v R ) 2 = 1 2 k x 2
_ 3 4 m v 2 = 1 2 k x 2
_ 3 4 _ 3 _ ( 4 ) 2 = 1 2 _ 200 x 2
_ 36 100 = x 2 _ x = 0.6 m