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QAIPM-2012-Ph-1745: NEET 2012 Physics - Class 12 AIPM-2012-Ph-1745 Solution: A spherical planet has a mass \(M_P\) and diameter \(D_P\). A…

A spherical planet has a mass MPM_P and diameter DPD_P. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity equal to 4GMPDP2\frac{4GM_P}{D_P^2} GMPmDP2\frac{GM_P m}{D_P^2} GMPDP2\frac{GM_P}{D_P^2} 4GMPmDP2\frac{4GM_P m}{D_P^2}

Multiple Choice Options

  • A 10 cm, 10 cm
  • B 15 cm, 5 cm
  • C 18 cm, 2 cm
  • D 11 cm, 9 cm

Step-by-Step Verified Solution

Magnifying power, m = f 0 f e = 9 ..........(1) where fo and fe are the focal lengths of the objective and eyepiece respectively Also,f o + f e = 20 cm ...(2) On solving (1) and (2), we get f o = 18 cm, f e = 2 cm

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