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QAIPM-2012-Ph-1739: NEET 2012 Physics - Class 11 AIPM-2012-Ph-1739 Solution: The motion of a particle along a straight line is described by…

The motion of a particle along a straight line is described by equation

x=8+12t-t^3

where

x

is in metre and

t

in second. The retardation of the particle when its velocity becomes zero is

Multiple Choice Options

A $24\ \text{m s}^{-2}$
B zero
C $6\ \text{m s}^{-2}$
D $12\ \text{m s}^{-2}$

Step-by-Step Verified Solution

Given x = 8 + 12t _ t 3 Velocity, v = d x d t = 12 - 3t 2 When v = 0, then 12 - 3t 2 = 0 _ t = 2 s a = d v d t = - 6t _ At t = 2 s, a = - 12 m/s 2 _ Retardation = 12 m/s 2

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