Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ph-1666: NEET 2012 Physics - Class 11 AIPM-2012-Ph-1666 Solution: An ideal gas goes from state A to state B via three different…

An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram. If Q1Q2Q3Q_1 Q_2 Q_3 indicate the heat absorbed by the gas along the three processes and ΔU1ΔU2ΔU3\Delta U_1 \Delta U_2 \Delta U_3 indicate the change in internal energy along the three processes respectively then Q1>Q2>Q3Q_1 > Q_2 > Q_3 and ΔU1=ΔU2=ΔU3\Delta U_1 = \Delta U_2 = \Delta U_3 Q3>Q2>Q1Q_3 > Q_2 > Q_1 and ΔU1=ΔU2=ΔU3\Delta U_1 = \Delta U_2 = \Delta U_3 Q1=Q2=Q3Q_1 = Q_2 = Q_3 and ΔU1>ΔU2>ΔU3\Delta U_1 > \Delta U_2 > \Delta U_3 Q3=Q2=Q1Q_3 = Q_2 = Q_1 and ΔU1>ΔU2>ΔU3\Delta U_1 > \Delta U_2 > \Delta U_3

Multiple Choice Options

  • A Q 1 > Q 2 > Q 3 and Δ\Delta _ U 1 = Δ\Delta _ U 2 = Δ\Delta _ U 3
  • B Q 3 > Q 2 > Q 1 and Δ\Delta _ U 1 = Δ\Delta _ U 2 = Δ\Delta _ U 3
  • C Q 1 = Q 2 = Q 3 and Δ\Delta _ U 1 > Δ\Delta _ U 2 > Δ\Delta _ U 3
  • D Q 3 = Q 2 = Q 1 and Δ\Delta _ U 1 > Δ\Delta _ U 2 > Δ\Delta _ U 3

Step-by-Step Verified Solution

Initial and final condition is same for all process _ U 1 = _ U 2 = _ U 3 from first law of thermodynamics _ Q = _ U + _ W Work done _ W 1 > _ W 2 > _ W 3    (Area of P.V. graph) So _ Q 1 > _ Q 2 > _ Q 3

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