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QAIPM-2012-Ph-1661: NEET 2012 Physics - Class 12 AIPM-2012-Ph-1661 Solution: Two radiations of photons energies 1 eV and 2.5 eV successively …
Two radiations of photons energies 1 eV and 2.5 eV successively illuminate a photosensitive metallic surface of work function 0.5 eV. The ratio of the maximum speeds of the emitted electrons is 1:4 1:2 1:1 1:5
Multiple Choice Options
- A 1:04
- B 1:02
- C 1:01
- D 1:05
Step-by-Step Verified Solution
According to Einsten�s photoelectric effect, the K.E. of the radiated electrons
K.E max = E � W
1 2 m v 1 2 = (1 - 0.5) eV = 0.5 eV
1 2 m v 2 2 = (2.5 - 0.5) eV = 2 eV
v 1 v 2 = 0.5 2 = 1 : 2