Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ph-1659: NEET 2012 Physics - Class 12 AIPM-2012-Ph-1659 Solution: For the angle of minimum deviation of a prism to be equal to…

For the angle of minimum deviation of a prism to be equal to its refracting angle the prism must be made of a material whose refractive index lies between

\sqrt{2}

and 1 lies between 2 and

\sqrt{2}

is less than 1 is greater than 2

Multiple Choice Options

A lies between $\sqrt 2$ 2 _ and 1
B lies between 2 and $\sqrt 2$ 2 _
C is less than 1
D is greater than 2

Step-by-Step Verified Solution

_ = sin _ ( _ m + A 2 ) sin _ ( A 2 ) = sin _ ( A + A 2 ) sin _ ( A 2 ) = sin _ A sin _ ( A 2 ) = 2 sin _ ( A 2 ) cos _ ( A 2 ) sin _ ( A 2 ) = 2 cos _ ( A 2 ) The angle of minimum deviation is given as _ min = i + e � A for minimum deviation _ min = A and i = e then 2A = i + i _ i = A i min = 0 = A min _ _ min = 2 i max = 90 0 = A max _ _ max = 2 _ _ lies between 2 and 2 .

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