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QAIPM-2012-Ph-1654: NEET 2012 Physics - Class 12 AIPM-2012-Ph-1654 Solution: A proton carrying 1 MeV kinetic energy is moving in a circular…
A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in uniform magnetic field. What should be the energy of an -particle to describe a circle of same radius in the same field? 2 MeV 1 MeV 0.5 MeV 4 MeV
Multiple Choice Options
- A 2 MeV
- B 1 MeV
- C 0.5 MeV
- D 4 MeV
Step-by-Step Verified Solution
According to the principal of circular motion in a magnetic field
F c = F m _ m v 2 R = q V B
_ R = m v q B = P q B = 2 m . k q B
R _ = 2 ( 4 m ) K _ 2 q B
R R _ = K K _
but R = R _ (given)
_ K = K' = 1 MeV