Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ph-1653: NEET 2012 Physics - Class 11 AIPM-2012-Ph-1653 Solution: If \(v_e\) is escape velocity and \(v_o\) is orbital velocity…

If vev_e is escape velocity and vov_o is orbital velocity of a satellite for orbit close to the earth's surface then these are related by vo=2vev_o = \sqrt{2v_e} vo=vev_o = v_e ve=2vov_e = \sqrt{2v_o} ve=2vov_e = 2v_o

Multiple Choice Options

  • A vo=2ve{v_o} = \sqrt {2{v_e}} v o _ = 2 v e _ _
  • B v o == = v e
  • C ve=2vo{v_e} = \sqrt {2{v_o}} v e _ = 2 v o _ _
  • D ve=2vo{v_e} = \sqrt 2 {v_o} v e _ = 2 _ v o _

Step-by-Step Verified Solution

Escapevelocity, v e = 2 G M R     ...(i) where M and R where M and R be the mass and radius of the earth respectively. The orbital velocity of a satellite close to the earth�s surface is v 0 = G M R    ...(ii) From (i) and (ii), we get v e = 2 v 0

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