Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ph-1648: NEET 2012 Physics - Class 11 AIPM-2012-Ph-1648 Solution: The dimensions of \(( _0 _0)^{-1/2}\) are \([L^{1/2}T^{-1/2}]\) …

The dimensions of (μ0ϵ0)−1/2(\mu_0\epsilon_0)^{-1/2} are [L1/2T−1/2][L^{1/2}T^{-1/2}] [L−1T][L^{-1}T] [LT−1][LT^{-1}] [L1/2T1/2][L^{1/2}T^{1/2}]

Multiple Choice Options

  • A [L1/2T−1/2]\left[ {{L^{1/2}}{T^{ - 1/2}}} \right] [ L 1/2 T _ 1/2 ]
  • B [L−1T]\left[ {{L^{ - 1}}T} \right] [ L _ 1 T ]
  • C [LT−1]\left[ {L{T^{ - 1}}} \right] [ L T _ 1 ]
  • D [L1/2T1/2]\left[ {{L^{1/2}}{T^{1/2}}} \right] [ L 1/2 T 1/2 ]

Step-by-Step Verified Solution

( _ 0 _ 0 ) _ 1 / 2 = 1 _ 0 _ 0 = Speed of light in vacuum = c So the dimension of ( _ 0 _ 0 ) _ 1 / 2 = [c] =[LT -1 ]

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