Verified Solution • 2025–26 Session
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QAIPM-2012-Ch-1718: NEET 2012 Chemistry - Class 11 AIPM-2012-Ch-1718 Solution: 50 mL of each gas A and of gas B takes 150 and 200 seconds…
50 mL of each gas A and of gas B takes 150 and 200 seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36, the molecular mass of gas A will be
Multiple Choice Options
- A 96
- B 128.74
- C 20.25
- D 64.42
Step-by-Step Verified Solution
According to Graham's law of diffusion,
r 1 r 2 = d 2 d 1 = M 2 M 1
r A = V A T A , r B = V B T B
V A / T A V B / T B = M B M A
V A = V B , T A = 150 sec , T B = 200 sec, M B = 36, M A = ?
T B T A = M B M A _ 200 150 = 36 M A
_ 4 3 = 36 M A o r 4 _ 4 3 _ 3 = 36 M A
_ M A = 36 4 _ 4 _ 3 _ 3 = 20.25