Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ch-1712: NEET 2012 Chemistry - Class 11 AIPM-2012-Ch-1712 Solution: pH of a saturated solution of \(Ba(OH)_2\) is 12. The value of…

pH of a saturated solution of Ba(OH)2Ba(OH)_2 is 12. The value of solubility product (KspK_{sp}) of Ba(OH)2Ba(OH)_2 is 3.3×10−73.3 \times 10^{-7} 5.0×10−75.0 \times 10^{-7} 4.0×10−64.0 \times 10^{-6} 5.0×10−65.0 \times 10^{-6}

Multiple Choice Options

  • A 37.56
  • B −- _ 43.76
  • C 43.76
  • D 40.66

Step-by-Step Verified Solution

H 2 O(l) _ 100 _ C H 2 O(g) �H o = 40.66kJ mol �1 �H o = �u o + _ n g RT _ n g = 1, R = 8.314 _ 10 �3 kJ mol �1 k �1 T = 100 + 273 = 373 K _ 40.66 = �u o + (1) (8.314 _ 10 �3 ) _ 373 _ �u o = 37.56 kJ mol �1

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