Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ch-1710: NEET 2012 Chemistry - Class 12 AIPM-2012-Ch-1710 Solution: In a reaction, \(A+B \) product, rate is doubled when the…

In a reaction, A+B→A+B\rightarrow product, rate is doubled when the concentration of B is doubled, and rate increases by a factor of 8 when the concentration of both the reactants (A and B) are doubled, rate law for the reaction can be written as

Multiple Choice Options

  • A rate = k[A][B]2k[A][B]^2
  • B rate = k[A]2[B]2k[A]^2[B]^2
  • C rate = k[A][B]k[A][B]
  • D rate = k[A]2[B]k[A]^2[B]

Step-by-Step Verified Solution

Rate of reaction for A + B _ Product Rate = k[A] x [B] y �(1) where, x and y are order w.r.t. A and B respectively. When the concentration of only B is doubled, the rate is doubled, so R� = k [A] x [2B] y = 2R �(2) If concentration of both the reactants A and B are doubled then the rate increases by a factor of 8 so R�� = k[2A] x [2B] y = 8R ...(3) = k2 x 2 y [A] x [B] y = 8R �(4) From equation (1) and (2), we get 2 R R = [ A ] x [ 2 B ] y [ A ] x [ B ] y _ 2 = 2 y _ y = 1 From equation (1) and (4), we get 8 R R = 2 x 2 y [ A ] x [ B ] y [ A ] x [ B ] y _ 8 = 2 x 2 y Substituting the value of y gives 2 x 2 1 = 8 _ 2 x = 4 _ x = 2 By replacing the values of x and y in rate law; rate = k[A] 2 [B]

Related Learning Resources & Exam Preparation